A particle executes SHM according to the equation, `y=4sin( pi t+(pi)/(3))`,where `y` is in `m` and `t` is in'`s` '.The phase of particle at time `t=0` is

A particle executes SHM according to equation x=10(cm)cos[2pit+(pi)/(2)] , where t is in seconds. The magnitude of the velocity of the particle at t=(1)/(6)s will be :-

A particle executing SHM according to the equation x=5cos(2pit+(pi)/(4)) in SI units. The displacement and acceleration of the particle at t=1.5 s is

A particle oscillates with S.H.M. according to the equation x = 10 cos ( 2pit + (pi)/(4)) . Its acceleration at t = 1.5 s is

A particle is performing SHM according to the equation x=(3cm)sin((2pit)/(18)+(pi)/(6)) , where t is in seconds. The distance travelled by the particle in 39 s is

A particle osciallates with SHM according to the equation x= (2.5 m ) cos [ ( 2pi t ) + (pi)/(4)] . Its speed at t = 1.5 s is

Position-time relationship of a particle executing simple harmonic motion is given by equation x=2sin(50pit+(2pi)/(3)) where x is in meters and time t is in seconds. What is the position of particle at t=0.5s ?

Position-time relationship of a particle executing simple harmonic motion is given by equation x=2sin(50pit+(2pi)/(3)) where x is in meters and time t is in seconds. What is the position of particle at t=1s ?

Position-time relationship of a particle executing simple harmonic motion is given by equation x=2sin(50pit+(2pi)/(3)) where x is in meters and time t is in seconds. What is the position of particle at t=0 ?

A particle moves in x-y plane according to the equations x= 4t^2+ 5t+ 16 and y=5t where x, y are in metre and t is in second. The acceleration of the particle is

A particle moves along y - axis according to the equation y("in cm") = 3 sin 100pi t + 8sin^(2) 50pi t - 6