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The frequency of oscillation of the magnet in an oscillation magnetometer in the earth's magnetic field is 40 oscillations per minute. A short bar magnet is placed to the north of the magnetometer, at a separation of 20cm from the oscillating magnet, with its north pole pointing towards north (figure). The frequency of oscillation is found to increase to 60 oscillations per minute. Calculate the magnetic moment of this short bar magnet. Horizonatl component of the earth's magnetic field is 24 muT .

The short hand of a clock is at 12 and the minutes hand is 3, then the time at that instant is _____.

A inductor of 20mH inductance and a resistor of 100 Omega resistance are connected in series to a battery of emf 10V. After a long time the circuit is short-circuited and the battery is disconnected. Find the current in the circuit 1 ms after short-circuiting.

An inductor (L = 100 mH) , a resistor (R = 100 Omega) , and a battery (W = 100 V) are initially connected in series as shown by the figure. After a long time the battery is disconnected after short circuiting the points A and B . The currents in the circuit 1 mm after the short circuit is

A bar magnet is put on the hanger of oscillation magnetometer and is made to oscillate in earth's magnetic field. Frequency of oscillation of bar magnet is found to be 3 Hz at a place where horizontal component of earth's magnetic field is 25 muT . Now a short magnet is placed to the north of magnetometer in such a manner that its North Pole points towards north. Distance of short magnet from the bar magnet hanging inside the magnetometer is 1 m. Frequency of oscillation now becomes 6 Hz. What is magnetic moment of short magnet?

It is a well known fact that during a total solar eclipes the disc of the moon almost completely covers the disc of the sun. From this fact and from the information you can gather from Solved Examples 3 and 4 on page 1//44, determine the approximate diameter of the moon.