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Three planets of same density have radii...

Three planets of same density have radii `R_(1),R_(2)` and `R_(3)` such that `R_(1) = 2R_(2) = 3R_(3)`. The gravitational field at their respective surfaces are `g_(1), g_(2)` and `g_(3)` and escape velocities from their surfaces are `upsilon_(1),upsilon_(2)` and `upsilon_(3)`, then

A

`(g_(1))/(g_(2))=(1)/2`

B

`(g_(1))/(g_(3))=3`

C

`(v_(1))/(v_(2))=4`

D

`(v_(1))/(v_(3))=1/3`

Text Solution

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The correct Answer is:
B
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