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For a particle undergoing SHM, displacem...

For a particle undergoing SHM, displacement from mean position is given according to the law : `x(t)=(10cm)sin((2pit)/45)`, where t is in seconds. The mean position of particle is located at x=2cm. The ratio of KE and PE of particle when it is at x cm =−3cm is (Assume PE at mean position is zero)

A

2

B

0.33

C

0.5

D

3

Text Solution

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The correct Answer is:
D
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