Alpha decay

A radioactive sample decays through two different decay processes alpha -decay and beta -decay. Half-life time for alpha −decay is 3h and half-life time for beta −decay is 6h . What will be the ratio of number of initial radioactive to the number of nuclei present after 6 h ?.

A radioactive nucleus can decay be either emitting an alpha particle or by emitting a beta particle. Probability of alpha decay is 75% while that of beta decay is 25% the decayconstatnt of alpha decay is lamda_(1) and that of beta decay is lamda_(2) is (lamda_(1))/(lamda_(2))

A nucleus X initially at rest, undergoes alpha decay according to the equation _Z^232Xrarr_90^AY+alpha What fraction of the total energy released in the decay will be the kinetic energy of the alpha particle?

Staements I: In alpha decay of different radioactive nuclides, the energy of alpha particles has been compared. It is found that as the energy of alpha particle increases the half-life of the decay goes on decreasing. Staements II: More is the energy in any decay process, more is the probability of decaying the nuclide which leads to faster rate of decay.

When a nucleus with atomic number Z and mass number A undergoes a radioactive decay process, (i) Both Z and A will decrease, if the process is alpha decay (ii) Z will decrease but A will not change, if the process is beta^(+)- decay (iii) Z will increase but A will not change, if the process is beta- decay (iv) Z and a will remain uncharged, if the prices is gamma decay

A nucleus X of mass M. intially at rest undergoes alpha decay according to the equation _(Z)^(A)Xrarr._(Z-2)^(A-4)Y+._(2)^(4)He The alpha particle emitted in the above proces is found to move in a circular track of radius r in a uniform magnetic field B. Then (mass and charge of alpha particle are m and q respectively)

By using the following atomic masses : ._(92)^(238)U = 238.05079u . ._(2)^(4)He = 4.00260u, ._(90)^(234)Th = 234.04363u . ._(1)^(1)H = 1.007834, ._(91)^(237)Pa = 237.065121u (i) Calculate the energy released during the alpha- decay of ._(92)^(238)U . (ii) Show that ._(92)^(238)U cannot spontaneously emit a proton.

Various rules of thumb have seen proposed by the scientific community to expalin the mode of radioactive decay by various radioisotopes. One of the major rules is called the n//p ratio. If all the known isotopes of the elemnts are plotted on a graph of number of neutrons (n) versus number of protons (p), it is observed that all isotopes lying outside of a ''stable'' n//p ratio region are radioactive as shown fig. The graph exhibits straight line behaviour with unit slope up to p=25 . Above p=25 , tgose isotopes with n//p ratios lying above the stable region usually undergo beta decay. Very heavy isotopes (pgt83) are unstable because of their relativley large nuclei and they undergo alpha decay. Gamma ray emission does not involve the release of a particle. It represnts a change in an atom from a higher energy level to a lower energy level. How would the radioisotope of magnesium with atomic mass 27 undergo radioactive decay?.

When nucleus of an electrically neutral atom undergoes a radioactive decay process, it will remain neutral after the decay if the process is (a) An alpha - decay (b) A bete^(o+) -decay (c ) A gamma -decay (d) A K - caputure process

When nucleus of an electrically neutral atom undergoes a radioactive decay process, it will remain neutral after the decay if the process is (a) An alpha - decay (b) A beta^(o+) -decay (c ) A gamma -decay (d) A K - capture process