The mean and the variance of a binomial distribution are 4 and 2 respectively. Then the probability of 2 successes

The mean and the variance of a binomial distribution are 4 and 2 respectively.then, the probabitly of 2 , successes is

IF the mean and the variance of a binomial distribution are 4 and 3 respectively ,then the probability of six successes is

IF the mean and the variance of a binomial distribution are 4 and 3 respectively , then the probability of six successes is

If the mean and the variance of a binomial distribution are 2 and 1 respectively , then the probability of atleast one success is

The mean and variance of a binomial distribution are 4 and 4/3 respectively, find P(X=1)dot

The mean and variance of a binomial distribution (p+q)^n are 20 and 16 respectively. Then, the pair (n,p) is

The mean and variance of a binomial distribution are (5)/(4) and (15)/(16) respectively, then value of p, is

If the mean and the variance of a binomial variable X are 2 and 1 respectively, then the probability that X takes a value greater than one is equal to:

If the sum and the product of the mean and variance of a Binomial Distribution are 1-8 and 0.8 respectively, find the probability distribution and the probability of at least one success

The sum and the product of the mean and variance of a binomial distribution are 24 and 128 respectively. Find the distribution.