Q 4 and Q5 EXERCISE 13.1

Given that P 12, Q = 5 and R = 13 also P+Q=R, then the angle between P and Q will be

If f(x) = px +q, where p and q are integers f (-1) = 1 and f (2) = 13, then p and q are

The line segment joining the points (3,\ -4) and (1,\ 2) is trisected at the points P and Q . If the coordinates of P and Q are (p ,\ -2) and (5//3,\ q) respectively. Find the values of p and q .

Given that p(1,2,-4) , Q (5,4, -6) and R (0,8,-10) are collinear find the ratio in which Q divides PR

Charges 4Q, q and Q and placed along x-axis at positions x=0,x=1//2 and x=1 , respectively. Find the value of q so that force on charge Q is zero

The points P (4, 1) and Q (-2, 4) are reflected in line y = 3. Find the co-ordinates of P', the image of P and Q', the image of Q.

For the system of equations x+y+z=4, y+2z=5 and x+y+pz=q to have no solution (A) p=1 and q=4 (B) p=1 and q!=4 (C) p!=1 and q=4 (D) p!=1 and q!=4

Six charges , q_1 = +1 mu C , q_2 = +3 mu C , q_3 = +4 mu C , q_4 = -2 mu C , q_5 = -3 mu C and q_6 = -3 mu C are placed on a sphee of radius 10 cm. The potential at centre of sphere is

If P(-1,5) is hormonic conjugate of Q(-13,9) with respect to A and B. If A=(5,3) then find the length AB

Add the following expressions using horizontal method : 4p + 3q , 4q + 3p and -5p - 5q