H and E

A hydrogen atom and a Li^(2+) ion are both in the second excited state. If l_H and l_(Li) are their respective electronic angular momenta, and E_H and E_(Li) their respective energies, then (a) l_H gt l_(Li) and |E_H| gt |E_(Li)| (b) l_H = l_(Li) and |E_H| lt |E_(Li)| (C ) l_H = l_(Li) and |E_H| gt |E_(Li)| (d) l_H lt l_(Li) and |E_H| lt|E_(Li)|

The difference in Delta H and Delta E for the combustion of methane at 25^(@)C would be :-

Reducing power required for reduction of nitrogen into two molecules of ammonia is (A) \(4H^{+},4e^{-}\) and 8ATP (B) \(6H^{+},6e^{-}\) and 12ATP (c) \(8H^{+},8e^{-}\)and 16ATP (D) \(2H^{+},2e^{-}\) and 4ATP

The dimensions of h//e ( h= Plank's constant and e= electronic charge ) are same as that of

Find the H.C.E. and L.C.M. of 6!,7!,8! .

Which is the correct thermal stability order of H_(2)E(E=O,S,Se,Te and Po) ?

A sum of Rs. 1300 is divided among P, Q, R and S such that (P^(prime)s s h a r e)/(Q^(prime)s s h a r e)=(Q^(prime)s s h a r e)/(R^(prime)s s h a r e)=(R^(prime)s s h a r e)/(S^(prime)s s h a r e)=2/3dot How much is Ps share? R s .140 b. R s .160 c. R s .240 d. R s .320

Standard electrode potentials of few half-cell reactions are given below : {:(MnO_4^(-)+8H^(+)+5e^(-) to Mn^(2+)+ 4H_2O,,E^@=1.51V),(Cr_2O_7^(2-)+14H^(+)+6e^(-)to 2Cr^(3+)+7H_2O,,E^@=1.33V),(Fe^(3+)+e^(-)to Fe^(2+),,E^@=0.77V),(Cl_2+2e^(-) to 2Cl^(-),,E^@=1.36):} Based on the above information match the column I with column II and mark the appropriate choice.

The H.C.E of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, the other is :