XRAY

Electrons with de - Brogli wavelengtyh lambda fall on the target in an X-ray tube.The cut off wavelength of the emitted Xrays is (a) lambda_0 = (2mclambda^2)/(h) (b) lambda_0 = (2h)/(mc) (c ) lambda_0 (2m^2 c^2 lambda^3)/(h^2) (d) lambda_0 = lambda