STD 6 MATHS CH 13 SVADHYAY 13.3

The value of "2sin"^(2)(pi)/(3)-"cos"^(2)(pi)/(6)+"tan"^(2)(pi)/(6) is equal to A. 7/12 B. 13/12 C. 13/4 D.- 13/12

Solve: 6x - 3y = 13, 2x + y =3

4/13 + 9/13 + 2/13 = ?/13

-8-(-5)=? (a) -3, (b) -13, (c) 13, (d) 3

6.If a=2+-8 and =4+3-4 then the magnitude of a+h is equal to :(6)13)( a) 13 (d) 13

13^3-13^2=

6a^(2) - 13a + 6 =?

Add the following: 3/13 + 7/13 + 1/13

Solve the following: 3/13 - 2/13 + 5/13