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Ch-14 Statistics Revision with Important Question || Mode || Term -2 || Class 10 Maths||GCS Edumitra

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Most important question class 10 chapter 4 Quadratic equation

Class 10 Exercise 10.2 Question 1 | CBSE Class 10 Ex -10.2 Q1 | NCERT | Class 10 Maths Chapter 10

In a binomial expansion (x_y)^n gretest term means numericaly greatest term and therefore greatest term in (x-y)^n and (x+y)^n are ame. I frth therm t_r be the greatest term in the expansion of (x+y)^n whose therms are all ositive, then t_rget_(r+1) and t_rget_=(r-1)i.e. t_r/t_mge1 and t_r/t_(r-)ge1 On the basis of above information answer the following question:If rth term is the greatest term in the expansion f (2-3x0^10 then r= (A) 5 (B) 6 (C) 7 (D) none of these

class 10 exercise 8.4 question 4 part 1and2

Consider matrix A=[a_(ij)]_(nxxn) . Form the matrix A-lamdal, lamda being a number, real of complex. A-lamdal=[{:(a_11-lamda,a_12,...,a_(1n)),(s_21,a_22-lamda,...,a_(2n)),(...,...,...,...),(a_(n1),a_(n2),...,a_(n n)-lamda):}] Then det (A-lamdaI)=(-1)^n[lamda^n+b_1lamda^(n-1)+b_2lamda^(n-2)+...+b_(n)] . An important rheorem tells us that the matrix A satisfies the equation X^n+b_1x^(n-1)+b_2x^(n-2)+...+b_2=0. This equation is called hte characteristic equation of A. For all the questions on theis passeage, take A=[{:(1,4),(2,3):}] The matrix A satisfies the matrix equation

In physical pendulum, the time period for small oscillation is given by T=2pisqrt((I)/(Mgd)) where I is the moment of inertial of the body about an axis passing through a pivoted point O and perpendicular to the plane of oscillation and d is the separation point between centre of gravity and the pivoted point. In the physical pendulum a speacial point exists where if we concentrate the entire mass of body, the resulting simple pendulum (w.r.t. pivot point O) will have the same time period as that of physical pendulum This point is termed centre of oscillation. T=2pisqrt((I)/(Mgd))=2pisqrt((L)/(g)) Moreover, this point possesses two other important remarkable properties: Property I: Time period of physical pendulum about the centre of oscillation (if it would be pivoted) is same as in the original case. Property II: If an impulse is applied at the centre of oscillatioin in the plane of oscillation, the effect of this impulse at pivoted point is zero. Because of this property, this point is also known as the centre of percussion. From the given information answer the following question: Q. A uniform rod of mass M and length L is pivoted about point O as shown in Figgt It is slightly rotated from its mean position so that it performs angular simple harmonic motion. For this physical pendulum, determine the time period oscillation.

Use Graph paper for this question. A survey regarding height ( in cm) of 60 boys belonging to Class 10 of a school was conducted. The following data was recorded. Taking 2 cm = height of 10 cm along one axis and 2 cm = 10 boys along the other axis draw an ogive of the above distribution. Use the graph to estimate the following : (iii) if above 158 cm is considered as the tall boys of the class. Find the number of boys in the class who are tall.

In a binomial expansion (x+y)^n gretest term means numericaly greatest term and therefore greatest term in (x-y)^n and (x+y)^n are ame. I frth therm t_r be the greatest term in the expansion of (x+y)^n whose therms are all ositive, then t_rget_(r+1) and t_rget_=(r-1)i.e. t_r/t_mge1 and t_r/t_(r-)ge1 ON the basis of above information answer the following question: Greatest term in the expansion of (2+3x0^10, whern x= 3/5 is (A) ^10C_5(18/5)^5 (B) ^10C_6(18/5)^6 (C) ^10C_4(18/5)^4 (D) none of these

Use Graph paper for this question. A survey regarding height ( in cm) of 60 boys belonging to Class 10 of a school was conducted. The following data was recorded. Taking 2 cm = height of 10 cm along one axis and 2 cm = 10 boys along the other axis draw an ogive of the above distribution. Use the graph to estimate the following : (i) the median