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Let vec(C )= vec(A)+vec(B) then...

Let `vec(C )= vec(A)+vec(B)` then

A

`|vec(C)|` is always greater then `|vec(A)|`

B

It is possible to have `|vec(C)| lt |vec(A)| and |vec(C)| lt |vec(B)|`

C

C is always equal to A + B

D

C is never equal to A + B

Text Solution

Verified by Experts

The correct Answer is:
B
`vec(C) = vec(A) + vec(B)`
`C_("max")= A+B, C_("min") = A- B`
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