Three concurrent force of the same magnitude are in equilibrium. What is the angle between the forces? Also name the triangle formed by the forces as sides.

Options

A. `60^(@)` equilateral triangle
B. `120^(@)` equilateral triangle
C. `120^(@), 30^(@), 30^(@)` an isosceles triangle
D. `120^(@)` an obtuse angled triangle

Answer

B

Explanation

If N forces or vector of equal magnitude, act on a point and resultant is zero

Then angle between any two forces or vector –
`= (360)/(N)= (360)/(3)= 120^(@)`