A particle is moving on a circular path of radius r with uniform velocity v. The change in velocity when the particle moves from P to Q is `(anglePOQ=40^@`)

Options

A. `2v cos 40^(@)`
B. `2v sin 40^(@)`
C. `2v sin 20^(@)`
D. `2v cos 20^(@)`

Answer

C

Explanation

Change in velocity of the particle `Delta v= 2v sin ((theta)/(2)) =2v sin 20^(@)`