ABCDEF is a regular hexagon with point O as centre. The value of `vec(AB)+vec(AC)+vec(AD)+vec(AE)+vec(AF)` is

Options

A. `vec(AO)`
B. `2 vec(AO)`
C. `4 vec(AO)`
D. `6 vec(AO)`

Answer

D

Explanation

`vec(AB) + vec(AC) + vec(AD) + vec(AE) + vec(AF)= vec(OA) + vec(OA) + 2 vec(OA) + vec(OA) + vec(OA)= 6(vec(OA)) = 6(vec(AO))`

`vec(AC)= vec(AO)`
[angle between `vec(AB) and vec(BC) " is " 120^(@)`]