The unit of absolute permittivity is

Options

A. Fm (farad-metre)
B. `Fm^(-1)` (farad/metre)
C. `Fm^(-2) ("farad/metre"^2)`
D. F (farad)

Answer

B

Explanation

`F=1/(4piepsilon_0).(q_1q_2)/(r^2)` and 1 farad `= ("1 coulomb")/("1 volt")`
`implies epsilon_0=(q_1q_2)/(4piFr^2) = ("Coulomb")/(((Nm)/("Coulomb"))m)= (1 "coulomb")/("1 volt meter")`
or `C=epsilon_0A/dimplies epsilon_0=Fm^(-1)`