Dimensions of `ohm` are same as that of (where h is Planck's constant and e is charge)

Options

A. h/e
B. `h^2//e`
C. `h//e^2`
D. `h^2e^2`

Answer

C

Explanation

ohm `= [ML^(2) T^(-3)A^(-2)]`
`[h/e^2]=([ML^2T^(-1)])/([A^2T^2])=[ML^2T^(-3)A^(-2)]`