If the dimensions of a physical quantity are given by `M^(a)L^(b)T^(c)`, then the physical quantity will be :

Options

A. Pressure if a = 1, b = -1, c = -2
B. Velocity if a = 1, b = 0, c = -1
C. Acceleration if a = 1, b = 1, c = -2
D. Force if a = 0, b = -1, c = -2

Answer

A

Explanation

Pressure `=F/A= [ML^(-1)T^(-2)]`