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Position of a body with acceleration a i...

Position of a body with acceleration `a` is given by `x=Ka^mt^n`, here t is time Find demension of m and n.

A

m = 1 , n = 1

B

= 1, n = 2

C

m = 2, n = 1

D

m = 2, n = 2

Text Solution

Verified by Experts

The correct Answer is:
B
Position of the body –
`x= ka^(m) xxt^(n)`
`[M^(0)LT^(0)]=[LT^(-2)]^(m) [T]^n =[L^mT^(-2m+n)]`
`m =1 , -2m +n = 0 implies n = 2`
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