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A student measures the time period of 10...

A student measures the time period of `100` ocillations of a simple pendulum four times. The data set is `90 s`, 91 s, 95 s, and 92 s`. If the minimum division in the measuring clock is `1 s`, then the reported men time should be:

A

`10%`

B

`30%`

C

`15%`

D

`20%`

Text Solution

Verified by Experts

The correct Answer is:
D
T = 2.5 sec, `DeltaT =1/2 sec = 0.5 sec`
The permissible error
`(DeltaT)/T xx100 = (0.5)/(2.5) xx100 = 20%`
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