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If the error in the measurement of radiu...

If the error in the measurement of radius of a sphere in `2%` then the error in the determination of volume of the spahere will be

A

`8%`

B

`2%`

C

`4%`

D

`6%`

Text Solution

Verified by Experts

The correct Answer is:
D
`(Deltar)/r xx100 = 2%`
Volume `(V) =4/3 pir^3`
`implies ((DeltaV)/V) xx100 = 3 (Deltar)/r xx100 = 3 xx2 = 6%`
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