Home
Class 11
PHYSICS
The period of oscillation of a simple pe...

The period of oscillation of a simple pendulum in the experiment is recorded as `2.63 s , 2.56 s , 2.42 s , 2.71 s , and 2.80 s`. Find the average absolute error.

A

0.1 s

B

0.11 s

C

0.01 s

D

1.0 s

Text Solution

Verified by Experts

The correct Answer is:
B
`T_("mean") = (2.63 + 2.56 + 2.42 + 2.71 + 2.80)/5`
`= 2.62 sec`
`DeltaT_("mean") = (|DeltaT_1|+|DeltaT_2|+|DeltaT_3|+|DeltaT_4|+|DeltaT_5|)/5`
`=(0.01 + 0.06 + 0.20 + 0.09 + 0.18)/5 = (0.54)/5 = 0.11 `sec
Promotional Banner

Topper's Solved these Questions

  • UNITS, DIMENSIONS AND MEASUREMENT

    ERRORLESS|Exercise PAST YEARS QUESTIONS |24 Videos

  • UNITS, DIMENSIONS AND MEASUREMENT

    ERRORLESS|Exercise ASSERTION & REASON |17 Videos

  • UNITS, DIMENSIONS AND MEASUREMENT

    ERRORLESS|Exercise NCERT BASED QUESTIONS (Dimensions)|84 Videos

  • TRANSMISSION OF HEAT

    ERRORLESS|Exercise Assertion & Reason|22 Videos

  • WAVES AND SOUND

    ERRORLESS|Exercise ASSERTION & REASON |25 Videos

Similar Questions

Explore conceptually related problems

In successive measurement, the reading of the period of oscillation of a simple pendulum were found to be 2.63s, 2.56s, 2.71s and 2.80s in an experiment. Calculate (i) mean value of the period oscillation (ii) absolute errer in each measurement (iii) mean absolute error (iv) releative error (v) percentage error and (vi) express the result in proper form.

If the period of a simple pendulum is 2s, then its frequency is 0.5 Hz

In an experiment, the time period measurements for an oscillating simple pendulum are 2.10s, 2.12s, 2.23s, 2.62s and 2.92s. Find the relative error and absolute error in the experiment.

In an experiment he readings for the time period of a simple pendulum are 2.63 s, 2.56 s, 2.42 s, 2.71s and 2.80 s. Calculate the relative error and the percentage error.

The mean value of period of oscillation of a simple pendulum in an expreiment is 2.825 s. The arithmetic mean of all the absolute errors is 0.11 s. Round off the period of simple pendulum to approximate number of significant figures. Given resson.

The time period of a simple pendulum is 0.2 s. What is its frequency of oscillation?

The period of oscillation of a simple pendulum is given by T=2pisqrt((l)/(g)) where l is about 100 cm and is known to have 1 mm accuracy. The period is about 2 s. The time of 100 oscillation is measrued by a stop watch of least count 0.1 s. The percentage error is g is

The time period of oscillation of a simple pendulum is sqrt(2)s . If its length is decreased to half of initial length, then its new period is

ERRORLESS-UNITS, DIMENSIONS AND MEASUREMENT-NCERT BASED QUESTIONS (Errors of Measurement)
  1. A physical quantity X is given by X=(2k^(3)l^(2))/(msqrt(n)) The p...

    Text Solution

    |

  2. The radius of a sphere is (2.6 pm 0.1) cm The percentage error u iis v...

    Text Solution

    |

  3. The period of oscillation of a simple pendulum in the experiment is re...

    Text Solution

    |

  4. According to Joule's law of heating , heat produced H = I^(2) Rt, wher...

    Text Solution

    |

  5. A physical quantity is given by X=M^(a)L^(b)T^(c). The percentage erro...

    Text Solution

    |

  6. In an experiment to measure the height of a bridge by dropping stone i...

    Text Solution

    |

  7. A student measures that distance traversed in free fall of a body, ini...

    Text Solution

    |

  8. The mass and volume of a body are found to be 5.00 pm 0.05 kg " and "...

    Text Solution

    |

  9. Measure of two quantities along with the precision of respective measu...

    Text Solution

    |

  10. A person measures two quantities as A = 1.0 m +- 0.2 m ,B = 2.0 m +- 0...

    Text Solution

    |

  11. A body travels uniformly a distance of (13.8pm0.2) m in a time (4.0pm0...

    Text Solution

    |

  12. A physical parameter a can be determined by measuring the parameters b...

    Text Solution

    |

  13. A physical quantity Y is expressed as Y= (p^2)/(r )((q)/(sqrt(s)))^3 ...

    Text Solution

    |

  14. In an experiment , the following observations were recorded: L = 2.8...

    Text Solution

    |

  15. The percentage errors in the measurement of length and time period of ...

    Text Solution

    |

  16. A physical quantity P is given by P=(A^(3)B^((1)/(2)))/(C^(-4)D^((3)/(...

    Text Solution

    |

  17. The values of two resistors are R(1)=(6+-0.3)kOmega and R(2)=(10+-0.2)...

    Text Solution

    |

  18. The number of significant figures in all the given numbers 25.12, 2009...

    Text Solution

    |

  19. If L=2.331cm,B=2.1cm, then L+B=

    Text Solution

    |

  20. If the length of rod A is 3.25 pm 0.01 cm and that of B is 4.19 pm 0.0...

    Text Solution

    |