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In an experiment , the following observa...

In an experiment , the following observations were recorded:
`L = 2.820 m , M = 3.00 kg , l = 0.087 cm , diameter , D = 0.041 cm`. Taking ` g = 9.81 m s^(-2)` and using the formula , `Y = ( 4MgL)/( pi D^(2) l)` , find the maximum permissible error in `Y`.

A

`7.96%`

B

`4.56%`

C

`6.50%`

D

`8.42%`

Text Solution

Verified by Experts

The correct Answer is:
C
`Y=(4MgL)/(piD^2l)`
`((DeltaY)/Y)xx100 =((Deltam)/m+(Deltag)/g+(DeltaL)/L+(2DeltaD)/D+(Deltal)/l)xx100`
`((0.01)/(3.00)+(0.01)/(9.81)+(0.001)/(2.820)+2xx(0.001)/(0.041)+(0.001)/(0.087))xx100`
`= 0.065 xx100 = 6.5%.`
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