The length and breadth of a rectangular sheet are 16.2 cm and 10.1cm, respectively. The area of the sheet in appropriate significant figures and error is

Options

A. `164 pm 3 cm^2`
B. `163.62 pm 2.6 cm^2`
C. `163.6 pm 2.6 cm^2`
D. `163.62 pm 3 cm^2`

Answer

A

Explanation

Given, Length `l = (16.2 pm 0.1)cm`
Breadth `b = (10.1 pm 0.1)cm,` Area `A = l xx b`
`= (16.2 cm)xx (10.1cm) = 163.62 cm^2`
Rounding off to three significant digits, area `A =164 cm^2`
`implies DeltaA = A xx(2.63)/(163.62) = 163.62 xx(2.63)/(163.62) = 2.63 cm^2`
`Delta A = 3cm^2` (By rounding off to one significant figure)
`:.` Area `A = A pm DeltaA = (164 pm3) cm^2`