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A screw gauge has least count of 0.01 mm...

A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale:
The pitch of the screw gauge is:

A

0.01mm

B

0.25mm

C

0.5mm

D

1.0mm

Text Solution

Verified by Experts

The correct Answer is:
C
Least count `= ("Pitch")/("Number of divisions on circular scale")`
`0.01 mm= ("Pitch")/50 implies "Pitch" = 0.5 mm`
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