A body of mass m is moving in a circle of radius r with a constant speed v, The force on the body is `(mv^(2))/(r )` and is directed towards the centre. What is the work done by the force in moving the body over half the circumference of the circle?

Options

A. `(mv^(2))/r xx pir`
B. Zero
C. `(mv^(2))/r^(2)`
D. `(pir^(2))/(mv^(2))`

Answer

B

Explanation

Work done = 0, because force and displacement are perpendicular to each other.