A particle moves in a circle of radius 5 cm with constant speed and time period `0.2pis`. The acceleration of the particle is

Options

A. `m//s^(2)`
B. `15m//s^(2)`
C. `25 m//s^(2)`
D. `36 m//s^(2)`

Answer

A

Explanation

`a = omega^(2)r = ((2pi)/T)^(2) r = ((2pi)/0.2pi)^(2) xx (5 xx 10^(-2))`
`rArr a = 5 m//s^(2)`