A particle moves in a circle of radius 25 cm at two revolutions per sec. The acceleration of the particle in `m//s^(2)` is:

Options

A. `pi^(2)`
B. `8pi^(2)`
C. `4pi^(2)`
D. `2pi^(2)`

Answer

C

Explanation

`r =25 cm= 0.25 cm, f = 2` rev/s
`a = omega^(2)r =(2pif)^(2) xx r = 4pi^(2) xx 4 xx 0.25`
`a = omega^(2)r = (2pif)^(2) xx r = (4pi^(2)) xx 4 xx 0.25`
`=4pi^(2) m//s^(2)`