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If the radius of curvature of the path o...

If the radius of curvature of the path of two particles of same masses are in the ratio `1 : 2`, then in order to have same centripetal force, their velocity, should be in the ratio of

A

`1:4`

B

`4:1`

C

`sqrt(2):1`

D

`1:sqrt(2)`

Text Solution

Verified by Experts

The correct Answer is:
D

`F = (mv^(2))/r rArr r = (mv^(2))/F` If m and F are constant.
`r prop v^(2) rArr v prop sqrt( r) rArr v_(1)/v_(2) = sqrt(r_(1)/r_(2)) = sqrt(1/2)`
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