If a particle covers half the circle of radius R with constant speed then

Options

A. Change in momentum is mvr
B. Change in K.E. Is `1//2 mv^(2)`
C. Change in K.E. is `mv^(2)`
D. Change in K.E. is zero

Answer

D

Explanation

Change in momentum,
`DeltaP = -mv - mv =-2mv`

But kinetic energy remains constant, as change in K.E. is zero.