If a cycle wheel of radius 4 m completes one revolution in two seconds. Then acceleration of a point on the cycle wheel will be

Options

A. `pi^(2) m//s^(2)`
B. `2pi^(2) m//s^(2)`
C. `4pi^(2) m//s^(2)`
D. `8pi m//s^(2)`

Answer

C

Explanation

`a = omega^(2)r = 4pi^(2) (1/2)^(2) xx 4 = 4pi^(2) m//s^(2)`