The length of second's hand in watch is `1 cm`. The change in Velocity of its tip in 15 seconds is

Options

A. Zero
B. `pi/(30sqrt(2))` cm/sec
C. `pi/30` cm/sec
D. `(pisqrt(2))/30` cm/sec

Answer

D

Explanation

`theta = 90^(@)`
Charge in velocity `=|Deltavecv| = 2v sin (theta//2)`
`= 2(romega) sin 45^(@)`
`= 2 xx r xx (2pi)/7 sin 45^(@)`
`= 2 xx r xx (2pi)/T sin 45^(@)`
`= (4pi)/(60sqrt(2)) cm/"sec" = (pisqrt(2))/30` cm/s