A motor cyclist moving with a velocity of 72 km/hour on a flat road takes a turn on the road at a point where the radius of curvature of the road is 20 meters . The acceleration due to gravity is `10m//sec^(2)`. In order to avoid skidding, he must not bend with respect to the vertical plane by an angle greater than

Options

A. `theta = tan^(-1)6`
B. `theta = tan^(-1)2`
C. `theta = tan^(-1)25.92`
D. `theta = tan^(-1)4`

Answer

B

Explanation

`b = 72 xx 5/18 = 20 m//s, r = 20 m` to avoid skidding
`tan theta = v^(2)/(rg) rArr theta = tan^(-1) (400/(20 xx 10)) = tan^(-1) (2)`