Three identical particles are joined together by a thread as shown in figure. All the three particles are moving in a horizontal plane. If the velocity of the outermost particle is `v_(0)`, then the ratio of tensions in the three sections of the string is `(T_(BC):T_(AB):T_(DA))`

Options

A. `3:5:7`
B. `3:4:5`
C. `7:11:6`
D. `3:5:6`

Answer

D

Explanation

`T_(3) = m omega^(2) (3l)`

`T_(2) - T_(3) = m omega^(2) (3r)`
`T_(1) - T_(2) = momega^(2)( r)`
`rArr T_(1) = momega^(2) (4r)`
`T_(1):T_(2) = 4:3`