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A particle at a distance of 1 m from the...

A particle at a distance of 1 m from the origin starts moving such that `dr//d theta = r`, where `(r, theta)` are polar coordinates. Then the angle between resultant velocity and tangential velocity component is

A

30 degrees

B

45 degrees

C

60 degrees

D

Dependent on where the particle is

Text Solution

Verified by Experts

The correct Answer is:
B
`(dr)/(d theta) = r = (ds)/(d theta) rArr (dr)/(dt) = (ds)/(dt) rArr v_(t) = v_(r)` So, `alpha = 45^(@)`
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