a projectile is fired from the surface of the earth with a velocity of `5ms^(-1)` and angle `theta` with the horizontal. Another projectile fired from another planet with a velocity of `3ms^(-1)` at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth.The value of the acceleration due to gravity on the planet is in `ms^(-2)` is given `(g=9.8 ms^(-2))`

Options

A. 16.3
B. 110.8
C. 3.5
D. 5.9

Answer

C

Explanation

`y = x tan theta - (gx^(2))/(2u^(2) cos^(2) theta)`
For equal trajectories for same angle of projection
`g/u^(2) `= constant
`rArr 9.8/5^(2) = g^(.)/3^(2)`
`g. = (9.8 xx 9)/25 = 3.528 m//s^(2) = 3.5 m//s^(2)`