One end of a string of length 1.0 m is tied to a body of mass 0.5 kg . It is whirled in a vertical circle with angular frequency `4 rads^(-1)`.The tension in the string when the body is at the lower most points of its motion will be equal to `(Take ,g =10ms^(-2))`

Options

A. 3 N
B. 5 N
C. 8 N
D. 13 N

Answer

D

Explanation

The tension in the string at the lower most point.
`T = mg + momega^(2)r`
`= 0.5 xx 10 + 0.5 xx 4^(2) xx 1 = 5 + 8 = 13 N`