One end of string of length `l` is connected to a particle on mass `m` and the other end is connected to a small peg on a smooth horizontal table. If the particle moves in circle with speed `v` the net force on the particle (directed toward centre) will be (`T` reprents the tension in the string):

Options

A. T
B. `T - (mv^(2))/l`
C. `T + (mv^(2))/l`
D. zero

Answer

A

Explanation

Here centripetal force is provided by tension in the string.
`T = F_(C ) = (mv^(2))/r`