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Two stones of masses m and 2m are whirle...

Two stones of masses `m` and `2m` are whirled in horizontal circles, the heavier one in a radius `(r)/(2)` and the lighter one in radius `r` . The tangential speed of light stone is `n` times that of the value heavier stone when they experience same centripetal forces. The value of `n` is:

A

3

B

4

C

1

D

2

Text Solution

Verified by Experts

The correct Answer is:
D

`F_( c) = (mv_(1)^(2))/r = (2mv_(2))^(2)/(r//2) = (4mv_(2))^(2)/(r//2) = (4mv_(2)^(2))/r`
`rArr v_(1) = 2v_(2)`
`therefore n = 2`
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