The velocity of a projectile at the init...

The velocity of a projectile at the initial point A is `(2hati+3hatj) m//s`. Its velocity (in m/s) at point B is

`2hati + 3hatj`

`-2hati - 3hatj`

`-2hati + 3hatj`

`2hati - 3hatj`

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The correct Answer is:

Velocity in 4th quadrant
`(x to +ve , y to -ve)`
`v = 2hati - 3hatj`

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