The potential energy of a particle under a conservative force is given by `U ( x) = ( x^(2) -3x)` J. The equilibrium position of the particle is at

Options

A. x = 1.5 m
B. x = 2m
C. x = 2.5 m
D. x = 3m

Answer

A

Explanation

`V(x) = (x^2 -3x)`
`F = -(dV)/(dx) =-(2x-3)`
For equilibrium position
`2x - 3 =0implies x =3/2 =1.5 m`