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A forcevecF=(7-2x+3x^(2)) N is applied o...

A force`vecF=(7-2x+3x^(2))` N is applied on a 2 kg mass which displaces it from x = 0 to x = 5 m. Work done in joule is -

A

70

B

270

C

35

D

135

Text Solution

Verified by Experts

The correct Answer is:
D
`W=int_0^5 Fdx = int_0^5(7-2x +3x^2)dx`
`=[7x - x^2 + x^3]_(0)^(5) [35 - 25 + 125] = 135`
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