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A spring with spring constant K when str...

A spring with spring constant `K` when stretched through `1 cm`, the potential energy is `U`. If it stretched by `4 cm`, the potential energy will be

A

4U

B

8U

C

16 U

D

2 U

Text Solution

Verified by Experts

The correct Answer is:
C
`U=1/2 kx^2 , U prop x^2`
`U/U_1 = (1/4)^2 , U_1 = 16 U`
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