If a spring extends by `x` on loading, then the energy stored by the spring is (if T is tension in the spring and k is spring constant)

Options

A. `T^2/(2k)`
B. `T^2/(2k^2)`
C. `(2k)/T^2`
D. `(2T^2)/k`

Answer

A

Explanation

`U=F^2/(2k) =T^2/(2k)" " ["As " U=1/2kx^2=1/2((kx)^2)/k =F^2/2k]`