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A bullet of mass 0.05 kg moving with a s...

A bullet of mass `0.05` kg moving with a speed of `80m//s` enters a wooden block and is stopped after a distance of 0.40 m The average resistive force exerted by the block on the bullet is:

A

300 N

B

20 N

C

400 N

D

40 N

Text Solution

Verified by Experts

The correct Answer is:
C
`W=DeltaK implies F xx S =1/2 xx 0.05(80)^2`
`implies F=(1/2xx0.05 xx80 xx80)/(0.4) = 400 N`
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