A 0.5 kg ball is thrown up with an initi...

A 0.5 kg ball is thrown up with an initial speed 14 m/s and reaches a maximum height of 8.0 m . How much energy is dissipated by air drag acting on the ball during the ascent

19.6Joule

4.9 Joule

10 Joule

9.8 Joule

Text Solution

Verified by Experts

The correct Answer is:

`H_("max")=u^2/(2g) =((14)^2)/(2xx9.8)=10 m`
Energy difference =
`mg(H_("max")-8) =0.5 xx 9.8 xx 2 = 9.8J.`

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