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A block of mass m slides from rest at a height H on a frictionless inclined plane as shown in the figure. It travels a distance d across a rough horizontal surface with coefficient of kinetic friction `mu` , and compresses a spring of spring k by a distance x before coming to rest momentarily. Then the spring extends and the block travels back attaining a final height of h. Then

A

`h=H - 2mu(d+x)`

B

`h=H+2mu(d+x)`

C

`h=H-2mud+ kx^2 //mg`

D

`h=H-2mu(d+x) +kx^2//2mg`

Text Solution

Verified by Experts

The correct Answer is:
A
`mgH - 2mu mg(d + x) -mgh = 0`
`h = H - 2mu(d+x)`
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