An engine pumps up `100 kg` water through a height of `10 m` in `5 s`. If efficiency of the engine is `60%`. What is the power of the engine? `Take g = 10 ms^(2)`.

Options

A. 3.3 kW
B. 0.33 kW
C. 0.033 kW
D. 33 kW

Answer

A

Explanation

`P = (100 xx10xx 10)/5 implies (mgh)/t implies P = 2kW`
`eta = ("Power output")/("Power input") implies 0.60 = (2xx10^3)/P_i`
`implies P_(i) = (2xx10^4)/6 = 3.33 kW`