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A neutron having a mass of 1.67 xx 10^(-...

A neutron having a mass of `1.67 xx 10^(-27) kg` and moving at `10^(8) m//s`collides with a deuteron at rest and sticks to it. If the mass of the deuteron is `3.33 xx 10^(-27) kg` then the speed of the combination is

A

`2.56xx10^3 m//s`

B

`2.98xx10^5 m//s`

C

`3.33xx10^7 m//s`

D

`5.01xx10^9 m//s`

Text Solution

Verified by Experts

The correct Answer is:
C
`m_n = 1.67 xx10^(-27) kg , u_1 = 10^(8) m//s`
`m_d = 2 xx1.67 xx10^(-27) kg , u_2 =0`
`1.67 xx10^(-27) xx10^8 = (m_n +m_d) v`
`implies v =(1.67 xx10^(27) xx10^8)/(3 xx1.67 xx10^(-27))=3.33 xx10^7 m//s`
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