A particle moves from a point (-2hati+5h...

A particle moves from a point `(-2hati+5hatj)` to `(4hatj+3hatk)` when a force of `(4hati+3hatj)N` is applied. How much work has been done by the force ?

2 J

8 J

11 J

5 J

Text Solution

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The correct Answer is:

`vecS= vecr_f -vecr_i = (4hatj + 3hatk) - (-2hati +5hatj) = 2hati - hatj + 3hatk and vecF = 4hati + 3hatj`
`omega = vecF.vecS = (4hati+ 3hatj). (2hati - hatj + 3hat k) = 8-3 = 5J`

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